Question

Prove the identity...

Answer 1

\[\frac{ \sin x \tan x }{ 1-\cos x }= 1 + \frac{ 1 }{ \cos x }\]

Answer 2

I have got up to
(1-c^2)/(c(1-c))

Answer 3

now for 1-c^2
use
\(a^2-b^2 = (a+b)(a-b)\)

Answer 4

So (1-c)(1+c)/c(1-c)

Answer 5

what gets cancelled out ?

Answer 6

(1-c)
Which leads to (1+c)/(c)

Answer 7

now separate th denominator...

Answer 8

I'm not so sure how to do that

Answer 9

ok, \(\huge \dfrac{a+b}{c}=\dfrac{a}{c}+\dfrac{b}{c}\)

Answer 10

1/c + c/c
= 1/c + 1
Thanks once again for your help!

Answer 11

you're welcome ^_^