Question

sqrt 8x^3

Answer 1

Are you solving that?

Answer 2

There is nothing to solve. Are you simplifying? \(\sqrt{8x^{3}}\)?

Answer 3

Yes, I need to simplify it. And if you will, please explain how you do it. Also, do you know to divide square roots by square roots?

Answer 4

Find all the perfect squares and pull them out.

\(\sqrt{8x^{3}} = \sqrt{2\cdot 4\cdot x^{2}\cdot x}\)

Those middle two factors look awfully tempting.

Answer 5

Change sqrt(8x^3) to sqrt(2*2*2*x*x*x). U can see that the square root of 4(2*2) is 2 and the square root of x^2 is x and what's left is 2x, so the radical simplified would be 2xsqrt(2x)

Answer 6

tkhunny, is that simplified? I am suppose to simplify as much as possible. But I do not understand how you do that. I am like algebra dumb. How did you get x\[^{2}\] and the other x?

Answer 7

snezzies, how did you do that?

Answer 8

That is right, YOU are supposed to simplify as much as possible. Take a good, hard look at those perfect squares under the radical and find a reason to move them outside the radical.

Answer 9

sqrt(2*2*2*x*x*x) is the same thing as sqrt(8x^3) I just broke it down. Then you can break it into sqrt(2)*sqrt(2)*sqrt(2)*sqrt(x)*sqrt(x)*sqrt(x). Sqrt(2)*sqrt(2) equals sqrt(4) because multiplying square roots you multiply the coefficient and what's inside the square root. You can do that to sqrt(x) * sqrt(x) too. It would be sqrt(x^2). Now you have sqrt(4)*sqrt(x^2)*sqrt(2)*sqrt(x). Sqaure root of 4 is 2. And sqrt of x^2 is x. So it's 2*x*sqrt(2)*sqrt(x). Multiply the sqrts together and it's sqrt(2x). So the answer is 2xsqrt(2x)