Question

Challenging Question :-



( NOT IN EXAMINATION POINT OF VIEW)

You have to identify the mistake in this challenging proof. (Given Below)


[ REMEMBER:- This proof is absolutely wrong. don't write this proof any more in examination..

It's just a challenge and use your brain to identify the mistake]

Thank You.
I hope all can answer this.

Answer 1

Proof of 4=5

\[\huge \bf 16-36=25-45\]
\[\huge \bf 16-36+\frac{81}{4}=25-45+\frac{81}{4}\]
\[\huge \bf (4-\frac{9}{2})^2=(5-\frac{9}{2})^2\]
\[\huge \bf 4-\frac{9}{2}=5-\frac{9}{2}\]
\[\huge \bf 4=5\]

Answer 2

Identify the mistake.

Answer 3

mistake while taking square root on both sides

Answer 4

the answer to \(\sqrt {x^2} = |x| \)

Answer 5

Goku always saving the day...

Answer 6

so infact , final answer will be
\(|4-9/2|=|5-9/2| \\ |-1/2|=|-1/2| \\ 1/2 = 1/2\)

Answer 7

This is true though:\[
\left| 4-\frac 92 \right| = \left|5-\frac 92\right|
\]

Answer 8

*************************************************
This is irrelevant!!!
*************************************************
\[ (4-\frac{9}{2})^2=(5-\frac{9}{2})^2\]\[ (4-\frac{9}{2})^2-(5-\frac{9}{2})^2=0\]\[ [(4-\frac{9}{2})+(5-\frac{9}{2})][(4-\frac{9}{2})+(5-\frac{9}{2})]=0\]\[ [9-2(\frac{9}{2})][(9-2(\frac{9}{2})]=0\]\[0\times0 = 0\]Lol! This is fun!

Answer 9

lol, what a nice proof that 0 x 0 = 0

Answer 10

Thanks LOL!

Answer 11

Goood.......going.........

Answer 12

Is this a direct proof, or a "I'm going to assume it is true because I know it is true, oh look it's true!" proof?

Answer 13

thank you . this is true proof

Answer 14

Ah-huh! I didn't know it turned out like that though :\