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Mathematics 13 Online
OpenStudy (anonymous):

what is the mass of 25.0cm^3 of gold

OpenStudy (anonymous):

What is the density you are given?

OpenStudy (anonymous):

hint : 1cm = 1 ml

OpenStudy (anonymous):

That doesn't really make sense and we need the density of gold.

OpenStudy (anonymous):

The density of gold is 19.3 gcm^-3 (sourced from the internet) So we rearrange rho = m/v to m = rho x v m = 19.3 x 25 = 482.5 g

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