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Mathematics 18 Online
OpenStudy (christos):

Calculus, Can you please help me solve this exersise ? http://screencast.com/t/ZCxLNCfm Thanks a lot

hartnn (hartnn):

you have a unit circle with u ?

OpenStudy (christos):

Unfortunately I am not sure what that is :/

OpenStudy (christos):

ok

hartnn (hartnn):

in that chart, the point is of the form (r cos theta, r sin theta) with r=1 (because of "unit")

OpenStudy (anonymous):

hey @hartnn dont you think you shud better suggest a trig table?

hartnn (hartnn):

so, where do u see the point where sin theta = -1 ?? (for sin^{-1} -1)

hartnn (hartnn):

table or circle, both give same info

OpenStudy (christos):

pi/2 ?

hartnn (hartnn):

for pi/2, the y co-ordinate (sin ) is +1 right ?

hartnn (hartnn):

where is y co-ordinate = -1 ? for which angle ?

OpenStudy (christos):

oh is it - pi/2 ?

OpenStudy (christos):

what do you mean which angle

hartnn (hartnn):

yes, -pi/2 or 3pi/2 is the correct angle

hartnn (hartnn):

all those are angels 0,pi/2,3pi/2,2pi

OpenStudy (christos):

so sin is -1 in those angles ?

hartnn (hartnn):

sin is -1 for -pi/2. 3pi/2 , 3pi/2 +2pi, and so on

OpenStudy (christos):

so the answer ot the first is -pi/2 ?

OpenStudy (christos):

Or I can also put 3pi/2 ?

hartnn (hartnn):

both are valid

hartnn (hartnn):

so can u also find c and d now ?

OpenStudy (christos):

Ok but why does it have a power of -1 above the sin ? How am I using the ^-1 information ?

hartnn (hartnn):

ok, its the inverse sin function! when \(\sin x =y \implies x = \sin^{-1}y\) also called arcsin y

OpenStudy (christos):

So sin (-1) (without the power) = -2/pi too ? or no ?

OpenStudy (christos):

I mean without the "inverse" sing **

hartnn (hartnn):

sin (-1) what that is ? sin of the angle -1 ?

OpenStudy (christos):

theta = -1

hartnn (hartnn):

sin (-1) = -sin 1 ....is just a small number .....not in terms of pi

OpenStudy (christos):

cant sin^(-1)(-1) be = -sin^(-1)(1) ? :P you see what I mean ?

hartnn (hartnn):

yes, thats true too, because sin -x = -sin x

hartnn (hartnn):

so, sin^-1 -1 = - sin^-1 1 = - (pi/2) which i said is valid too :)

OpenStudy (christos):

so why if we put the inverse sign that grants us the bility to express it in terms of pi and without the inverse sign we can't do that?

OpenStudy (christos):

hmm

hartnn (hartnn):

because \(\sin^{-1}.....\) will give you AN ANGEL!

OpenStudy (christos):

oooh

hartnn (hartnn):

because we always take sin of angels!

OpenStudy (christos):

second one is pi/2 or 0 ?

OpenStudy (christos):

and/or ****

hartnn (hartnn):

forget about tan inverse for now, first do c and d by looking at unit circle

OpenStudy (christos):

ok hold on

OpenStudy (christos):

c is pi/3 ?

OpenStudy (christos):

pi/6 * * * *

hartnn (hartnn):

pi/3 right ? because sin inverse and you see y co-ordinate for sin

OpenStudy (christos):

I see. Is 2pi/3 correct as well ?

hartnn (hartnn):

yes, yes, good

hartnn (hartnn):

what about d ? which 2 angles ?

OpenStudy (christos):

pi/3 and 5pi/3

hartnn (hartnn):

wasn't that easy ? :) now sec^{-1}-2 = cos^{-1} (-1/2) = ... ?

OpenStudy (christos):

hmmm 2pi/3 and 4pi/3 ? Btw how did you make that conversion inside the parenthesis ? (-2) = (-1/2)

hartnn (hartnn):

have a look at inverse trogo formulas whn u have time http://en.wikipedia.org/wiki/Inverse_trigonometric_functions

hartnn (hartnn):

there's a formula for that

OpenStudy (christos):

hmm i see

hartnn (hartnn):

the 1st one in reciprocal arguments

hartnn (hartnn):

so only tan inverse remains, right ?

OpenStudy (christos):

yea !

hartnn (hartnn):

you know tan = sin/cos so, tan =1 only when sin = cos right ?? so for what values of angles, are sin and cos equal ?? find that from circle

OpenStudy (christos):

pi/4 , 5pi/4 ??

hartnn (hartnn):

:) correct!

hartnn (hartnn):

because for tan pi/4 and tan 5pi/4, the answer will be =1

hartnn (hartnn):

hence tan inverse of 1 will be pi/4 or 5pi/4

OpenStudy (christos):

:D I see ! ! Thanks a lot for the clarifications ! ^_^

hartnn (hartnn):

welcome ^_^

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