Calculus, Can you please help me solve this exersise ? http://screencast.com/t/ZCxLNCfm Thanks a lot
you have a unit circle with u ?
Unfortunately I am not sure what that is :/
ok
in that chart, the point is of the form (r cos theta, r sin theta) with r=1 (because of "unit")
hey @hartnn dont you think you shud better suggest a trig table?
so, where do u see the point where sin theta = -1 ?? (for sin^{-1} -1)
table or circle, both give same info
pi/2 ?
for pi/2, the y co-ordinate (sin ) is +1 right ?
where is y co-ordinate = -1 ? for which angle ?
oh is it - pi/2 ?
what do you mean which angle
yes, -pi/2 or 3pi/2 is the correct angle
all those are angels 0,pi/2,3pi/2,2pi
so sin is -1 in those angles ?
sin is -1 for -pi/2. 3pi/2 , 3pi/2 +2pi, and so on
so the answer ot the first is -pi/2 ?
Or I can also put 3pi/2 ?
both are valid
so can u also find c and d now ?
Ok but why does it have a power of -1 above the sin ? How am I using the ^-1 information ?
ok, its the inverse sin function! when \(\sin x =y \implies x = \sin^{-1}y\) also called arcsin y
So sin (-1) (without the power) = -2/pi too ? or no ?
I mean without the "inverse" sing **
sin (-1) what that is ? sin of the angle -1 ?
theta = -1
sin (-1) = -sin 1 ....is just a small number .....not in terms of pi
cant sin^(-1)(-1) be = -sin^(-1)(1) ? :P you see what I mean ?
yes, thats true too, because sin -x = -sin x
so, sin^-1 -1 = - sin^-1 1 = - (pi/2) which i said is valid too :)
so why if we put the inverse sign that grants us the bility to express it in terms of pi and without the inverse sign we can't do that?
hmm
because \(\sin^{-1}.....\) will give you AN ANGEL!
oooh
because we always take sin of angels!
second one is pi/2 or 0 ?
and/or ****
forget about tan inverse for now, first do c and d by looking at unit circle
ok hold on
c is pi/3 ?
pi/6 * * * *
pi/3 right ? because sin inverse and you see y co-ordinate for sin
I see. Is 2pi/3 correct as well ?
yes, yes, good
what about d ? which 2 angles ?
pi/3 and 5pi/3
wasn't that easy ? :) now sec^{-1}-2 = cos^{-1} (-1/2) = ... ?
hmmm 2pi/3 and 4pi/3 ? Btw how did you make that conversion inside the parenthesis ? (-2) = (-1/2)
have a look at inverse trogo formulas whn u have time http://en.wikipedia.org/wiki/Inverse_trigonometric_functions
there's a formula for that
hmm i see
the 1st one in reciprocal arguments
so only tan inverse remains, right ?
yea !
you know tan = sin/cos so, tan =1 only when sin = cos right ?? so for what values of angles, are sin and cos equal ?? find that from circle
pi/4 , 5pi/4 ??
:) correct!
because for tan pi/4 and tan 5pi/4, the answer will be =1
hence tan inverse of 1 will be pi/4 or 5pi/4
:D I see ! ! Thanks a lot for the clarifications ! ^_^
welcome ^_^
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