Question

Newton's 2nd Law:

Answer 1

what is the definition of equivalent mass when taking into account the frictional force in an Atwood Machine

I solved the following Theoretical Acceleration, but when I checked a textbook, I found that when considering frictional force Equivalent Mass has to be added to the total mass being accelerated
https://docs.google.com/file/d/0B1KXu57eJmDyY2FvbUtQTW5wRHM/edit?usp=sharing

Answer 2

so now it would be
\[a=\frac{ (m_2-m_1)g }{ (m_1+m_2+m_{eq}) }\]

Answer 3

summoning physics expert and or math enthusiasts to come to my rescue

Answer 4

@ganeshie8 @UnkleRhaukus

Answer 5

friction

Answer 6

dont you need a friction force opposing the motion ?

Answer 7

take three cases, m_1 { > , < , = } m_2

Answer 8

YES. I forgot to deduct the friction.
\[F-f=(m_1+m_2+m_{eq})a\]
\[(m_2-m_1)g-f=(m_1+m_2+m_{eq})a\]
so,
\[a=\frac{ (m_2-m_1)g-f}{ m_1+m_2+m_{eq} }\]

but what I want to really know is the "equivalent mass."

Answer 9

Acceleration of the objects is directly proportional to the net or resultant force acting on it and inversely proportional to the mass of the object.

F = m × a

Where,
'F' is the force applied to the object
'm' is the mass of the object, Unit of mass is kilograms (kg).
'a' is the acceleration of the object

More information on Newton's 2nd Law http://goo.gl/jSmzMF