"write an equation for the linear function f satisfying the given conditions" f(-3)=8 and f(1)=4
f(-3)=12
I need to know how to show my work for this type of problem
im in algebra 2 part 1 so.... do you want to put it into y=mx+b?
yes
ok take one problem f(-3)=8 im going to solve for x first
\[f(-3)=8\] add 3 to both sides x=11
solve for y f(1)=4 subtract 1 from both sides y=3
plug x and y in to one equation
f(y)=mx+b f(3)=1(11)+4 f(3)=7 subtract 3 from both sides slope is 4
then its simple y=mx+b 3=4(11)+4
3=48?
im confused. I have to write an equation using the above f(-3)=8 and f(1)=4
Can you find two points using f(-3)=8 and f(1)=4?
(-3 , 1 ) ?
For f(-3)=8, there is an x of -3 and a y of 8 --> (-3,8) For f(1)=4, there is an x of 1 and a y of 4 --> (1,4)
Oh ok, so now that I know my x's and y's how would I set that up as an equation showing my work
Use the equation \[m=\frac{ y _{2}-y _{1} }{ x _{2}-x _{1} }\] to find your slope and then you could either use y=mx+b or point-slope formula
thanks
You're welcome.
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