HELP!
f(x)=t-2/3t+7
for 1/f(x)

Question

HELP!
f(x)=t-2/3t+7
for 1/f(x)

anonymous · Answer

@Matthew071

john_es · Answer

Do yo mean,
$$f^{-1}(x)$$
or
$$\frac{1}{f(x)}$$
?

anonymous · Answer

the 2nd one

john_es · Answer

Well, then you only have to put it this way,
$$\frac{1}{t-\frac{2}{3t}+7}$$I'm not sure if you write 2/(3t) or 2/3*t.

john_es · Answer

And I think this is a strange problem, asking to find that.

hartnn · Answer

i think its $\large \dfrac{t-2}{3t+7}$

can we have the entire question ??

anonymous · Answer

i am confused :@

anonymous · Answer

what i have posted is the entire question.

john_es · Answer

If @hartnn is correct, then, they are asking you for the inverse function, so it is,
$$f^{-1}(x)$$

hartnn · Answer

"for 1/f(x)" <<<<<<is not a question.....

john_es · Answer

True.

anonymous · Answer

they have given me this function f(x)= t-2/3t+7
and said to find 1/f(x)

anonymous · Answer

i mean f(t)= t-2/3t+7

john_es · Answer

But must be as @hartnn wrote it,
f(t)= (t-2)/(3t+7)

anonymous · Answer

yeah

hartnn · Answer

to get 1/f(t) you just flip the numerator and denom. 
$\large \dfrac{f(t)}{1}=\dfrac{t-2}{3t+7} \ \large \implies \dfrac{1}{f(t)}=\dfrac{3t+7}{t-2}$
thats it!

anonymous · Answer

that is exactly what i did, but i was confused whether it was right or wrong :/

hartnn · Answer

it is correct.

anonymous · Answer

thanks :)

hartnn · Answer

welcome ^_^