Question

write the expression in radical notation (16^1/2)^-3

Answer 1

\[(16^{\frac{1}{2}})^{-3}=\frac{1}{16^\frac{3}{2}}=\frac{1}{\sqrt[2]{16^3}}\]

Answer 2

(16^1/2)^-3
\[16^{1/2} = \sqrt{16} \]
(x)^-3
\[x^{-3} = \frac {1 }{x^3}\]

Answer 3

Just to point out,
\[\sqrt{16^3}=(\sqrt{16})^3\]