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Mathematics 17 Online
OpenStudy (anonymous):

I can only use 1 variable to write and solve an equation for the following question: "The length of a rectangular field is 10 meters less than 4 times its width. It costs $1584 to put a fence around the field. If the fencing costs $4.80 per meter, what is the area of the field?" What is my equation? (only 1 variable!)

OpenStudy (ranga):

Assume w to be the width (the one variable we will use is w). What is the length?

OpenStudy (anonymous):

The length is not given. I have to find the length and the width based on the price of each meter for fencing and the total price.

OpenStudy (ranga):

No. From the problem description you can first derive the length in terms of the variable w. If width = w length = 4w - 10 ("The length of a rectangular field is 10 meters less than 4 times its width.") Now Perimeter = ? (use the width and length in the previous two lines) Perimeter =

OpenStudy (anonymous):

Would my equation (in simplest form) be 5w - 10?

OpenStudy (ranga):

There are two length and two widths to a rectangle. So the perimeter will be the sum of all four sides.

OpenStudy (anonymous):

So it would be 10w -20? And also, I need to know what it would equal. (Ex. 10w-20=?)

OpenStudy (ranga):

Yes we will get to that. I am just doing a step-by=step walk through. So the perimeter = 10w - 20. Keep this aside for the time being. Reading the problem further we can find the numerical value of the perimeter. It costs $4.80 per meter and the total cost to put the fence around the perimeter is $1584. So how many meters is the perimeter based on these two numbers?

OpenStudy (anonymous):

The perimeter is 330 meters.

OpenStudy (ranga):

Yes. Now we calculated the perimeter earlier at 10w - 20 = 330. Solve for w.

OpenStudy (anonymous):

w = 35

OpenStudy (ranga):

And length = ?

OpenStudy (anonymous):

The length is 130 meters

OpenStudy (ranga):

Area = ?

OpenStudy (anonymous):

The area is 4550 meters

OpenStudy (ranga):

Yep!

OpenStudy (anonymous):

Thank you so much for all of your help!

OpenStudy (ranga):

no problem.

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