x*(-x) = 0 right?
@dan815 @Euler271
x*x*-1 can be written as -x^2 it is only 0 if x is 0
well im asking because this is my question: (x-3)(x+3) +3y - x + 2 = (x-2)\[(x-3)(x+3) +3y - x + 2 = (x-2)^{2}+y\]
ignore that first thing :)
and im eliminating the brackets now...
so far i got 2x+3x+3xy and now im stuck
what are you solving for ? the variable y ?
x and y
so could you help me get rid of the brackets please? @phi
you are confusing me. you can solve for 2 variables only if you have 2 equations do you have 2 equations ?
all i want to do for now, is get rid of the brackets :)
\[(x-3)(x+3) +3y - x + 2 = (x-2)^{2}+y\]
for that
you can multiply them people use FOIL
(x-3)(x+3) = x^2 - 9
im doing it a different way.. x*x x*3 x*3y x*-x x*2
well that is a little long...
how can i use FOIL for this?
(x+3)(x-3) First: x*x or x^2 Outer x*-3 or -3x Inner: 3x Last: 3*-3 = -9 add up to get x^2 -3x+3x -9 -3x +3x is 0, so you can simplify to x^2 - 9
though people memorize that (a+b)(a-b)= a^2 - b^2 that formula works for (x+3)(x-3) they also use that formula to factor a^2 - b^2 to get (a+b)(a-b)...
hm okay so now i got x^2-9+3y-x+2=(x-2)^2+y how do i get rid of the second bracket now?
same way... (x-2)^2 is the same as (x-2)(x-2) use FOIL: x^2 -2x -2x +4 or x^2 -4x +4
oh okayyyy :)
x^2-9+3y-x+2=x^2-4x +4+y
so this is how it should look like?
yes but you can simplify it. It will turn into an equation for a line
simplified it should look like this? -9+2y+2=-3x+4
you can combine all the numbers
i dont understand... i am wrong?
you are correct. but -9 +2 is -7 if you add 7 to both sides you get -9+2y+2=-3x+4 2y - 7 = -3x +4 2y = -3x + 11 if you now divide by 2 you get y = (-3/2) x + 11/2 which is the equation of a line with slope -3/2 and y-intercept of 11/2
but you added =7 to the first equation 2 times and to the second once... you can do that?
+7
sorry
I was not clear. I meant we start with what you found -9+2y+2=-3x+4 I then simplified -9 + 2 to get -7 on the left side 2y - 7 = -3x + 4 now add 7 to both sides to get 2y = -3x +11 and finally, divide both sides by 2 y = (-3/2) x + 11/2
ahh now i see :)
so 2/2 = 1 = y
yes, on the left side of the equation
but I would say 2y/2 = (2/2) * y = 1* y = y
i dont see how you got (-3/2) though
ohhh im sorry, i do
\[\frac{ 2y}{2} = \frac{-3x +11}{2} \]
nevermind, silly mistake
-3/2 = 0.6
11/2 = 5.5
-3/2 = -0.6
-3/2 is -1.5 but people often leave the answer as a fraction
oh, okay
y= 1.5x+5.5
y=3x
is that right?
y= -1.5x + 5.5 (you lost a minus sign) that is as simple as you can get it, unless you have another equation it is the equation of a line, and all the points on the line will make your original messy equation true.
oh but wait, i have to have a number for y and x... it dosent make sense ;/
@phi
Yes, I think you should post the original question. See if you can take a screen shot of the actual question and post it
\[(x-3)(x+3) +3y - x + 2 = (x-2)^{2}+y\]
this was the original question :) how my teacher wrote it on the board
and was there any other information? Your complicated equation simplifies to what we found y = -1.5 x + 5.5 but to find a particular x,y we need more information here is wolfram's solution of your equation http://www.wolframalpha.com/input/?i=%28x-3%29%28x%2B3%29+%2B3y+-+x+%2B+2+%3D+%28x-2%29%5E2%2By
omg im sorry, i forgot to post it!
\[(x-3)(x+3) +3y - x + 2 = (x-2)^{2}+y-2x+y=2\]
all that time D;
so that simplified is: -9+3y+2=-3x+4-2x=2
right?
I would pick just one expression or the other (we only need 1 more equation) For example, pick (x-3)(x+3) +3y - x + 2 = 2 or x^2 - 9 + 3y - x + 2 = 2 we can simplify
-9+3y+2=-3x+4-2x=2
it cant be this?
then it would be -7+3y=x=2
we already used the first two \[ (x-3)(x+3) +3y - x + 2 = (x-2)^{2}+y-2x+y \] now we want to use another equation, such as \[ (x-3)(x+3) +3y - x + 2 = 2\]
We should start with the original expression... I don't see how to get to -9+3y+2=-3x+4-2x=2... that is probably not correct. so start with \[ (x-3)(x+3) +3y - x + 2 = 2 \]
how does that = 2?
your teacher wrote A=B=2 where A is one complicated thing, and B is another complicated thing. but if A=B and B=2 then A=2
ohhh i see, okayv :)
we could use the other expression... I think both are equally difficult (or easy) to solve
so what now?
can you simplify \[ (x-3)(x+3) +3y - x + 2 = 2 \] solve for 3y
(x-3)(x+3)
you should get (x-3)(x+3) + 3y - x +2 = 2 x^2 -9 +3y -x =0 3y= -x^2 + x + 9
we know from the first two equations that y= -1.5x+5.5 use that in 3y= -x^2 + x + 9 3( -1.5x +5.5) = - x^2 + x +9 <-- replaced y with -1.5x+5.5 -4.5x + 16.5 = -x^2 + x + 9 <-- distribute the 3 x^2 -5.5x +7.5=0 <--- simplified multiply both sides by 2 to get 2x^2 -11x +15 = 0 factor into (2x - 5)(x-3) = 0 solve for x. You get two different answers find y using y= -1.5x+5.5
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