Question

how to find asymototes on a trig graph?

Answer 1

That would depend on the functions used. Examples?

Answer 2

some functions will have such, usually a vertical asymptote only, like tangent or secant, check their graph

Answer 3

y=tan(x) and y=cot(x). my graphing calculator graphs them incorrectly and i have a test and want to know how to do them by hand.

Answer 4

i also wish to know how to graph these, 6csc(6(x+3)

Answer 5

http://graphcalc.com/download.shtml <--- graphic calc

Answer 6

thank you, but like on the test i want to know how to like check if i am doing it right.

Answer 7

as you may recall for rational functions, the vertical asymptotes are at the zeros for the denominator, thus
\(\bf tan(\theta) = \cfrac{sin(\theta)}{cos(\theta)}\\ \quad \\
\textit{setting}\quad cos(\theta) = 0\\ \quad \\
cos(\theta) = 0\implies cos^{-1}(cos(\theta)) = cos^{-1}(0)\implies \theta = cos^{-1}(0)\)

Answer 8

so the vertical asymptotes for tangent, will be at those angles, where the cosine is 0, like 0, or \(\large \pi, 2\pi, 3\pi...\)

Answer 9

hmm wait... dohh.. ahemmm anyhow, not those angles... but the \(\bf \cfrac{\pi}{2},\cfrac{3\pi}{2}, \cfrac{5\pi}{2}...\)

Answer 10

i see, thank you. that makes alot of sense now. how would i graph csc and sec? like what are tips?

Answer 11

most calculators, do not show a csc or sec function, but you can always just use \(\bf csc(\theta) = \cfrac{1}{sin(\theta)}\qquad \qquad sec(\theta) = \cfrac{1}{cos(\theta)}\)

Answer 12

if the amplitude is bigger than 1 would i put it in as 2/sin?

Answer 13

hmm yes, for an amplitude of "2", yes, \(\bf \cfrac{2}{sin(\theta)}\implies 2csc(\theta)\)

Answer 14

alright, thanks alot

Answer 15

yw