Are none of these correct? http://gyazo.com/745606c90f816ad7775f92bf3322c9bb
@Psymon
Nah, one of them is correct.
B
Right.
Got it for some reason it was a little off on my calculator and looked weird.
I see, lol. Yeah, they wanted y-values, so little funky even when I looked at it. Whatever xD
What about this question? http://gyazo.com/24acbbe0522ad0b54adb144787a69772
Well thats a bit ridiculous
How so?:O I just don't know how to do it.
Just the numbers xDD No need to have friggin billionths and trillionths place decimals xD
Am I supposed to find the maximum, then input that into the equation to find the year..?
But nah, nothing new. But yeah, find the maximum, so derivative, set equal to 0
Lol I just use my calculators maximum and minimum :(
Is that bad?
Should learn to do it yourself, lol
How do I? Find the derivative and set it equal to zero then thats it? solve for the variable and then I get my maximum?
Right. You may get more than one value when you set the derivative to 0, so itd be up to you to test all your values into the ORIGINAL function, and see which is highest.
And what about minimum?
2.8184 at t=71.6973
Same thing. for example, you set derivative to 0 and get t = 1 and 2. Plug them both into the original equation. Highest answer is max, lowest answer is minimum. If you only get one answer for t in the derivative, its up to you to determine if the point is a max or min, usually by using end behavior and knowledge of graphs.
Gotcha:)
Yep, sounds good for the max. So t is 71.6973. Add that to 1910 to find the year.
1982?
Yeah, if you round :3
Yes for the years:O But it said round down so its 1981. So what about for the 2003 and 2010?
Plug in t = 93 into the original first.
Got ti atll, thanks man.
Alright, awesome :3
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