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OpenStudy (anonymous):
\[\frac{cx}{d+f}=b\] right?
OpenStudy (anonymous):
\[\frac{ cx }{ d+f }=b\]
OpenStudy (anonymous):
Yes
OpenStudy (anonymous):
and what is the question?
OpenStudy (anonymous):
How to solve it
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OpenStudy (anonymous):
solve for \(x\) ?
OpenStudy (anonymous):
No solve for b
OpenStudy (anonymous):
\(b\) is already solved for as it is by itself on one side of the equal sign
OpenStudy (anonymous):
b is already solved for haha
OpenStudy (anonymous):
So how do I answer
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OpenStudy (anonymous):
I don't understand what you're asking?
Are you solving for x because b is already solved for...?
OpenStudy (anonymous):
Sorry yes solve for x
OpenStudy (anonymous):
\[x=b(d+f)/c\]
OpenStudy (anonymous):
Don't let letters scare you.
OpenStudy (anonymous):
Ok so that's the answer but how do come up with answer?
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OpenStudy (anonymous):
It's the same algebra as it would be with numbers.
OpenStudy (anonymous):
Please show how to work it
OpenStudy (anonymous):
\[\frac{ cx }{ d+f}=b\]
\[cx = b(d+f)\] because you multiply each side to cancel d+f on the left.
\[x=\frac{ b(d+f) }{ c }\] divide by c because you want to get rid of it from the left side.