Question

13/(-3+2i)

Answer 1

\[\frac{13}{-3+2i}\times \frac{-3-2i}{-3-2i}=\frac{13(-3-2i)}{3^2+2^2}\]

Answer 2

\[\frac{ 13 }{ -3 +2i }\]

Answer 3

always multiply top and bottom by the conjuate of the denominator
this works becase \((a+bi)(a-bi)=a^2+b^2\) a real number

Answer 4

So the denominator is 5?

Answer 5

oh not it is not \(3+2\) it is \(3^2+2^2\)

Answer 6

13? Since 3 squared equals 9 and 2i x -2x = - 4i^2 which equals four

Answer 7

yes, the denominator is \(13\)

Answer 8

which very conveniently cancels with the \(13\) up top, giving a final answer of \(-3-2i\)

Answer 9

I see! Awesome, thank you!

Answer 10

yw