Ask your own question, for FREE!
Chemistry 8 Online
OpenStudy (anonymous):

How to find molecular formula if molar mass of CH2O is 870 g/mol?

OpenStudy (jfraser):

\(CH_2O\) is an EMPIRICAL formula, the lowest possible whole number ratio. The molecular formula will have the same ratio, but with more pieces of each atom. The empirical formula has a mass: the empirical mass:\[(12g + 2(1g) + 16g) = 40g\]the actual formula has a mass of 840g. What should you multiple the empirical mass by to get the actual mass?

OpenStudy (anonymous):

it is 30g=40g... :| So confusing

OpenStudy (jfraser):

sorry, 30g.

OpenStudy (anonymous):

multiply 28..?

OpenStudy (jfraser):

ok, so the actual mass is 28 times larger than the empirical mass. the actual formula MUST HAVE the same multiple of pieces take \(CH_2O\) and multiply each piece by 28 and you'll have a compound with the same ratio, and a mass of 840g

OpenStudy (anonymous):

wait.. C28H56N28? :D

OpenStudy (jfraser):

does that have a mass of 840g and have the same ratio as \(CH_2O\)?

OpenStudy (anonymous):

Yes, i think so..

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!