How to find molecular formula if molar mass of CH2O is 870 g/mol?
\(CH_2O\) is an EMPIRICAL formula, the lowest possible whole number ratio. The molecular formula will have the same ratio, but with more pieces of each atom. The empirical formula has a mass: the empirical mass:\[(12g + 2(1g) + 16g) = 40g\]the actual formula has a mass of 840g. What should you multiple the empirical mass by to get the actual mass?
it is 30g=40g... :| So confusing
sorry, 30g.
multiply 28..?
ok, so the actual mass is 28 times larger than the empirical mass. the actual formula MUST HAVE the same multiple of pieces take \(CH_2O\) and multiply each piece by 28 and you'll have a compound with the same ratio, and a mass of 840g
wait.. C28H56N28? :D
does that have a mass of 840g and have the same ratio as \(CH_2O\)?
Yes, i think so..
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