Can someone please help!? D:
there may be more than one answer, but 1) is true because \[P(A)=\frac{1}{6},P(B)=\frac{1}{2}\] and since they are independent, \[P(A\cap B)=\frac{1}{6}\times \frac{1}{2}=\frac{1}{12}\]
It is multiple choice, like, select all that apply
in fact, from what i have written above, we see that all are true except C
I just really don't get any of it lol
How is C not true?
you roll a die how many sides does it have?
6
how many sides has a 5 on it?
1?
right what is the probability therefore that you "roll a 5"?
1/6
k so you got that one right? \(P(A)=\frac{1}{6}\)
how many of the sides have even numbers on them?
3
k good so what is the probability that you roll an even number?
3/6
right, reduce
1/2
k so \(P(B)=\frac{1}{2}\) seems like you are not having too much trouble
No lol I get it all now. Thanks man you always help me decent lol
in fact i would argue that it is rather straight forward right? the only thing left to understand it that \(A\cap B\) means the first die is a 5 and the second is even,and to find \(P(A\cap B)\) you multiply the two numbers together, giving \[P(A\cap B)=\frac{1}{6}\times \frac{1}{2}=\frac{1}{12}\]
yw
Join our real-time social learning platform and learn together with your friends!