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Mathematics 8 Online
OpenStudy (anonymous):

Two boys want to use a seesaw and they need to move the seesaw so that their weights will balance out. The formula is given by w1 • d1 = w2 • d2 where w1 = weight of the first boy, d1 = distance of the first boy from the fulcrum, w2 = weight of the second boy, and d2 = distance of the second boy from the fulcrum. Rewrite the formula to solve for d2. Show all steps in your work

OpenStudy (anonymous):

@greenlegodude57

OpenStudy (anonymous):

Oh I did this a week or two ago.

OpenStudy (anonymous):

To solve for d2 get d2 by itself on one side of the equal sign.

OpenStudy (anonymous):

We can do that by dividing w2 to both sides: So we have: w1 x d1/w2 = d2 So: d2 = w1 x d1/w2 is your equation.

OpenStudy (anonymous):

I wish my algebra was this easy :(

OpenStudy (anonymous):

Soo.. d2= w1 x d1/w2 is the equation... Now thats all?

OpenStudy (anonymous):

I thought you did this like a week ago? haha

OpenStudy (anonymous):

Yes that's your equation that's all you have to do . . .

OpenStudy (anonymous):

A few weeks ago actually . . . I'm deeper into the course now . . .

OpenStudy (anonymous):

Oh god.. you got me scared .. lol

OpenStudy (anonymous):

??? How??

OpenStudy (anonymous):

because math is my week spot.. & goin in deep its DEEP

OpenStudy (anonymous):

Will you help me with another plz? @greenlegodude57

OpenStudy (anonymous):

Um, okay . . .

OpenStudy (anonymous):

The area of this figure can be found by the formula A = (wh) + 0.5(bh). If Marcie wants the total area to be larger than a specified value, she can use the formula A > (wh)+ 0.5(bh). Rewrite this formula to solve for b. Show all steps in your work.

OpenStudy (anonymous):

OpenStudy (anonymous):

Lets see, um, A > (wh) + 1/2(bh) 2A > (wh) + (bh) 2A - (wh) > (bh) 2A - wh/h > b

OpenStudy (anonymous):

So your equation is b < 2A - wh/h

OpenStudy (anonymous):

Your awesome!! Btw how do I give you a medal? I just never realized how to give them out lol

OpenStudy (anonymous):

Click the "Best Response" thing on one of my responses.

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