What is the derivative of e^x? Why?
depends on what your definition of \(e^x\) is
one definition is that \(e\) is the number that makes \[\lim_{h\to 0}\frac{e^h-1}{h}=1\] true
the answer to the first question is that the derivative of \(e^x\) is \(e^x\) but the "why" depends entirely on how you define the function \(e^x\)
Oh I see. Thank you so much! I remember learning that the derivative of e^x is e^x and I was just confused as to why.
@satellite73 this was also confusing to me. is there a mathematical proof involved?
https://www.khanacademy.org/math/calculus/differential-calculus/der_common_functions/v/proof--d-dx-e-x----e-x i tried searching this on google. this video will probably help @iGunwoo
Ah. This website as well as KhanAcademy are my saviors, haha. Thanks a lot! @jolee
at the risk of repeating myself, you cannot show that the derivative of \(e^x\) is \(e^x\) without having a precise definition of \(e^x\) or at the very least of \(e\)
much as i like khan, this video assumes facts not in evidence, as they say on perry mason
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