Jeannie has some $10 bills and some $20 bills.if she has 273 bills worth a total of $4370,how many of the bills are $10 bills and how many are $20 bills.?

Question

hero · Answer

$x=$ Number of ten dollar bills
$y = $ Number of twenty dollar bills        

        $x +y = 273$
$10x + 20y = 4370$

anonymous · Answer

Can you solved it for me

hero · Answer

Have you tried solving it?

anonymous · Answer

Yes But I am not familiar with this kind of equation thats why I need someone to help me

hero · Answer

Which are you more familiar with...

Solving systems of equations by elimination or substitution?

anonymous · Answer

None am new in math

hero · Answer

To solve by elimination:

Multiply both sides of the equation x+y=273 by 10:

Then you'll have the following system:
10x+10y=2730
10x+20y=4370

Swap the rows to make it convenient for subtraction:

10x+20y=4370
10x+10y=2730

Subtract the second equation from the first to eliminate x variable:

10y=1640

Divide both sides by 10
y=164

Plug the value for y back in to the original equation to solve for x:

The original equation was:

x+y=273

If y=164 then 

x+164=273
x=273−164
x=109

So there are 109 ten dollar bills and 164 twenty dollar bills. 

If we check this we get:

109(10)+164(20)=4370