Question

The probability of obtaining the sequence {H, T, T, T} when you toss a fair coin 4 times equals

A. 1/16
B. 1/4
C. 1/2
D. 1/32

Answer 1

does the sequence oder matter?

Answer 2

*order

Answer 3

It doesn't say so I assume no

Answer 4

sequence tends to mean order is important:

the sequence; heads first, tails next, tails again, and finally a tail ... is a sequence of events

Answer 5

Ohh ok well scratch what I just said lol

Answer 6

since 1/24 isnt an option, id assume order doesnt matter in this case

Answer 7

Ohhh ok ok I get it. Got confused for a second lol

Answer 8

\[P(h=1):\binom{4}{1}.5^4\]

Answer 9

if order matters: there are 2^4 different orders

hhhh

hhht
hhth
hthh
thhh

hhtt
htht
thht
htth
thth
tthh

httt
thtt
ttht
ttth

tttt

16 different sequences

Answer 10

1/16 if the order of the sequence matters is what i see. I was thinking of 4! for some reason to start with

Answer 11

Wow... wait, so it was 1/16 and reduced to 1/4?

Answer 12

I'm lost D:<

Answer 13

if order matter, then the sequence of events: httt is 1 out of 16: 1/16

if order is not important and the combination of 1head, 3 tails is important: there are 4 out of 16 ways to get it. 4/16 = 1/4

im pretty sure since they say the "sequence" {h,t,t,t} its refering to the order as important. But im always about half right on these things :)

Answer 14

Ohhhhhh ok ok I understand. Well I'll go with 1/4 and I'll tell you if it was correct or not

Answer 15

I mean 1/16

Answer 16

lol, good luck