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Mathematics 20 Online
OpenStudy (christos):

Inverse functions, I have to solve this problem: http://screencast.com/t/Yiw1NBSg1qH I am stuck in this step: http://screencast.com/t/ZZ0swLbzbCx I know it's simple but I know it's gonna drain the life outa me to find out just how to proceed , can you help me out ??

hartnn (hartnn):

\(\int x^ndx= x^{n+1}/(n+1)+c\) n=1/2 here

OpenStudy (christos):

It's my first time solving an integral to such level of complexity btw so I just wanna make sure since I am learning alone and I dont have anyone to verify that I am going right exept myself

OpenStudy (christos):

hm hold on

OpenStudy (anonymous):

did you how they got to the step where you are struck?

OpenStudy (christos):

ofc

OpenStudy (anonymous):

that's good .. hartnn just told you how to do this you got that?

OpenStudy (christos):

ok so it's 2u^(3/2)/3 can you please tell me what then ? I just need to see some minor details that are really hard to express on message I just need to see the logic on first one with u sub + limited int

OpenStudy (anonymous):

now put the value of u that's it ..

hartnn (hartnn):

now just put the limits, put upper limit, and subtract the lower limit from it

OpenStudy (anonymous):

and then put the limits

OpenStudy (christos):

After replacing u or before ??

OpenStudy (anonymous):

okay let's get confused

hartnn (hartnn):

you don't replace u

hartnn (hartnn):

since we have changed the limits, we need nor do a plugging back

hartnn (hartnn):

forget that u ever had an ex

OpenStudy (christos):

"since we have changed the limits" Changed them to what ?

OpenStudy (anonymous):

i think no need to replace u we have changed limits

hartnn (hartnn):

a variable 'x' i mean :P

OpenStudy (anonymous):

i did't saw we changed limits sorry for that

hartnn (hartnn):

from 1 to sqrt 3 to pi/4 to pi/3

hartnn (hartnn):

from (x=1 to sqrt 3) to (u=pi/4 to pi/3)`

OpenStudy (christos):

soo final answer : sqrt(pi/3) - sqrt(pi/4) ?

hartnn (hartnn):

"2u^(3/2)/3"<-----why didn't u put it in this ??

OpenStudy (christos):

oh I am sorry you are right ! : 2(pi/3)^(3/2)/3 - 2(pi/4)^(3/2)/3 good ?

hartnn (hartnn):

yeah correct...see whether it gets simplified, if you need it to be more simplified...

OpenStudy (christos):

I see, will do, thankies !

hartnn (hartnn):

welcomies!

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