Question

helpppp....

The perimeter of a rectangle is 256 inches. How long are the sides if the length exceeds the width by 16 inches?

Mark lets x represent the width of the rectangle and writes the equation 2x + 2(x + 16) = 256. Solving for x, the width of the rectangle is


56
60
68

Answer 1

perimeter = 2*a + 2*b

if a=x, then b=x+16

Answer 2

i don't know what i am subpose to do....

Answer 3

@khofer you have to algebraically solve
2x + 2(x + 16) = 256

Answer 4

The perimeter of a rectangle is 256 inches. find the length if it exceeds the width by 16 inches.

We need the formula P = 2l + 2w

You are given the perimeter to be 256 inches.

We are also told that:

width = x

length = x + 16

Then: 256 = 2(x + 16) + 2x

256 = 2x + 32 + 2x

256 = 2x + 32

256 - 32 = 4x

224 = 4x

224/4 = x

56 = x

Answer 5

ok i got it thank u sooooo much...

Answer 6

My Pleasure.