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Mathematics 8 Online
OpenStudy (anonymous):

Please help Quick questions

OpenStudy (anonymous):

OpenStudy (anonymous):

@iambatman @some_someone @Opcode

OpenStudy (ineedserioushelp):

Good luck getting help on those lol 0_0

OpenStudy (anonymous):

@some_someone can you help me?

OpenStudy (anonymous):

Okay, for #2 do you know what to factor out?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

the coefficients are: 16, 2, -22 so what is the least common factor of the three of them?

OpenStudy (anonymous):

2

OpenStudy (anonymous):

good

OpenStudy (anonymous):

i think 2 is a am i correct?

OpenStudy (anonymous):

not quite

OpenStudy (anonymous):

ohh okay

OpenStudy (anonymous):

16a^3b^7 + 2a^6b^4 - 22a^4b^5 so far we have: factor out a 2, but we also need to factor out some of the varaibles

OpenStudy (anonymous):

is it d since you factor some out?

OpenStudy (anonymous):

no not quite

OpenStudy (anonymous):

16a^3b^7 + 2a^6b^4 - 22a^4b^5 so need to factor out the lowest factor of the variable a and variable b? do you understand me, because it might sound kind of confusing i got to admit.

OpenStudy (anonymous):

so we factor out the lowest degree of the variable. i.e we factor out a^3 and b^4 so we factor out a 2a^3b^4 out of 16a^3b^7 + 2a^6b^4 - 22a^4b^5

OpenStudy (anonymous):

i guess little it so i know there will be a 2 outside the parenthesis right?

OpenStudy (anonymous):

\[16a^3b^7 + 2a^6b^4 - 22a^4b^5\] \[2a^3b^4(-----)\]

OpenStudy (anonymous):

okay so its b

OpenStudy (anonymous):

okay lets do 3 i think its c or a

OpenStudy (anonymous):

yes, but do you know why and how?

OpenStudy (anonymous):

which one?

OpenStudy (anonymous):

for #2

OpenStudy (anonymous):

ohh because of the least common factor for eact

OpenStudy (anonymous):

yeah okay seem like you understood most of the process for #2. lets move on to #3 and verify you are understanding (:

OpenStudy (anonymous):

do you know what to do for #3, now that we did #2?

OpenStudy (anonymous):

find the least comon factor for each?

OpenStudy (anonymous):

yes, try it (:

OpenStudy (anonymous):

okay they all go into 9 so its 9x exponents subtract i think

OpenStudy (anonymous):

does 9 go into 3?

OpenStudy (anonymous):

coefficients: 3, 18, 27

OpenStudy (anonymous):

so what is the least common factor that goes into all three of those coefficients?

OpenStudy (anonymous):

3

OpenStudy (anonymous):

3 nvm

OpenStudy (anonymous):

good (: well not 1, because it obviously goes into any number lol, so 3 would be correct.

OpenStudy (anonymous):

now the variables: x^3, x^2, x

OpenStudy (anonymous):

1 so is it c or b @some_someone

OpenStudy (anonymous):

yes its one of those

OpenStudy (anonymous):

but from the variables we would factor out an x

OpenStudy (anonymous):

so we would factor out a 3x

OpenStudy (anonymous):

3x(______)

OpenStudy (anonymous):

can you do that?

OpenStudy (anonymous):

yes x3+6x3+9x2

OpenStudy (anonymous):

3x^3 + 18x^2 + 27x factor out a 3x so: 3x(x^2 + 6x + 9) your not done yet u have to factor the thing inside the ( )

OpenStudy (anonymous):

how?

OpenStudy (anonymous):

have you done any related problems like these? Maybe you have notes or something?

OpenStudy (anonymous):

You seem very lost; sorry to say it.

OpenStudy (anonymous):

no this is like a before quiz pre test

OpenStudy (anonymous):

ouh so u have not been introduced to this material?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

so please gve me the answr ans an explenation so i can understand them

OpenStudy (anonymous):

@some_someone is 3 c?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

okay can you do 6 with an explanation so i can take notes ?

OpenStudy (anonymous):

what would u factor out? take in mind the 2 other problems we did

OpenStudy (anonymous):

3 the 30 and the 75 they all go into 3

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

what about from the variables?

OpenStudy (anonymous):

take the smallest one with the smallest degree(exponent)

OpenStudy (anonymous):

is it c

OpenStudy (anonymous):

YES!!! GOOD JOB (: I feel happy, your understanding a little better now, you are doing good.

OpenStudy (anonymous):

for 7 is it b?

OpenStudy (anonymous):

you could still factor it and reduce more

OpenStudy (anonymous):

a?

OpenStudy (anonymous):

if there is a - and a + then it would be a - and there is no negatives

OpenStudy (anonymous):

so c?

OpenStudy (anonymous):

\[5c^5 + 60^4 + 180^3\] \[5c^3(c^2 + 12c + 36)\] what two factors multiply to +36 and adds to +12?

OpenStudy (anonymous):

6?

OpenStudy (anonymous):

\[5c^3(c+6)(c+6)\] \[5c^3(c+6)^2\]

OpenStudy (anonymous):

yes good job (:

OpenStudy (anonymous):

okay 10 i dont understadn

OpenStudy (anonymous):

lets take a look

OpenStudy (anonymous):

\[d^4 - 8d^2 + 16\]

OpenStudy (anonymous):

we're going to have (....)(....)

OpenStudy (anonymous):

(d^2....)(d^2....) do you know why?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

because if you FOIL back, d^2 * d^2 = d^4 which is the 1st term in ur expression

OpenStudy (anonymous):

ohh okay is it a?

OpenStudy (anonymous):

no, (d^2 - 4)(d^2+4) will give you: d^4 + 4d^2 -4d^2 - 16

OpenStudy (anonymous):

ohh okay so its b

OpenStudy (anonymous):

@some_someone

OpenStudy (anonymous):

yep

OpenStudy (anonymous):

thanks

OpenStudy (anonymous):

no prob

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