Given the trinomial 5x^2-2x-3, predict the type of solutions.
A) 2 rational solutions B) 1 rational solution C) 2 irrational solutions D) 2 complex solutions
calculated the value of the determinant which for the equation a^2 + bx + c = 0 is b^2 - 4ac
Huh?
compare ax^2 + bx + c = 0 to 5x^2 - 2x - 3 = 0 so a = 5, b = -2 and c = -3 now plug these values into b^2 - 4ac and see what you get
the result will tell you the nature of the solutions of your equation
do you follow me?
The result was 56, right?
So the answer would be B?
(-2)^2 - 4*5*-3 = 4 + 60 = 64
if there is an expression in the form of ax^2 + bx + c = 0 then the expression b^2 - 4ac which is formed by the coefficient of x and the constant value of the above equation is known as the determinant. if that value is greater than 0 ----> there 2 Real solutions equal to 0 -----> there is only one soultion greater than 0 and is a square value ----> 2 rational answers greater than 0 and is not a square value ----> 2 irrational answers
a positive result means there are 2 rational roots so its A
Oh thank you!
@cwrw238 a positive result for the determinant means there r 2 REAL roots not 2 rational roots
It has to be a square value and a positive value to have 2 rational roots... however ur answer is correct cause 64 is a positive value and 64 = 8^2
yes - i missed that - my answer was correct partly by accident!
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