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Algebra 53 Online
OpenStudy (anonymous):

Solve 3x - 4 ≤ 2 or 2x + 11 ≥ -1. {x | x ≤ 2} {x | -6 ≤ x ≤ 2} {all reals}

OpenStudy (mathstudent55):

Start by solving each inequality. Can you do that?

OpenStudy (anonymous):

if i did i wouldnt be here aasking for help help me :(

OpenStudy (cwrw238):

I'll start it for you 3x - 4 ≤ 2 3x ≤ 6 x ≤ ? 2x + 11 ≥ -1 2x ≥ -12 x ≥ ? can you complete these ?

OpenStudy (anonymous):

?=2

OpenStudy (mathstudent55):

Don't take this the wrong way. You are trying to solve a compound inequality. That is two inequalities linked by the word "or." I'm trying to figure out if you need help with the fact that it is a compound inequality, or if you need help with just each inequality. The only way I can determine what kind of help you need is by asking.

OpenStudy (anonymous):

so it would be the first one?

OpenStudy (cwrw238):

yes

OpenStudy (anonymous):

thank you cwrw238

OpenStudy (cwrw238):

x ≤ 2 is correct for the first one

OpenStudy (mathstudent55):

Start with the first inequality: 3x - 4 ≤ 2 Add 4 to both sides: 3x ≤ 6 Divide both sides by 3: x ≤ 2 Now we work on the second inequality: 2x + 11 ≥ -1 Subtract 11 from both sides: 2x ≥ -12 Divide both sides by 2: x ≥ -6 Now you need to think about this result. If x ≤ 2 OR x ≥ -6, then all values of x are ok. The answer is C {all reals}.

OpenStudy (cwrw238):

do you follow that ok?

OpenStudy (cwrw238):

do you understand why all values of x fit the 2 inequalities

OpenStudy (cwrw238):

drawing a number line should help |dw:1381175381197:dw|

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