Question

Rate of Change

Answer 1

what does ROC mean?

Answer 2

oh hey there lol Rate of Change @Loser66

Answer 3

@jdoe0001

Answer 4

I just am having trouble with the points..

Answer 5

hmm I was thinking it was a derivative.... but ... ahemmm dunno

Answer 6

what class is this for?

Answer 7

well the formula is f(b)-f(a)/b-a

Answer 8

@calliendra for calc class

Answer 9

where b is y2 and a is y1

Answer 10

jdoe i was thinking take derivitive too... but it seems too easy for a calc question

Answer 11

i mean f(b) is y2 and f(a) is y1

Answer 12

right..... I was thinking about those lines.... pick 2 points and divide the y by the x
more or less RISE over RUN

Answer 13

yes @calliendra i just dont know what points to take to put it into my equation

Answer 14

@jdoe0001 yeah but which points. I know 0,4 is one but how about the other coordinates?

Answer 15

ooops sorry. ok for the rate of chang are you on derivitives?
if you take yprime and plug in for 2 you get slope at 2

Answer 16

for over the whole interval i would use the first and last points

Answer 17

yeah for rate of change im on derivates

Answer 18

ok
for the first i would find rise/run for the entire interval {0,4}
for the second take the derivitive of the line and plug in 2 for the x

Answer 19

okay i will try this suggestion in an hour because i have class right now

Answer 20

oh ok GOOD LUCK!!!

Answer 21

@Mertsj

Answer 22

Judging by the image, you have a parabola with three "known" points (not certain, but I'm basing it off of the given grid):
\[(0,-1),~(4,-1)\]
The average rate of change over \([0,4]\) is
\[\frac{f(4)-f(0)}{4-0}=\frac{-1-(-1)}{4}=0\]
The part that says not to use any computations is implying that you should see there is no relative change in \(f(x)\) from one end of the interval to the other.

Answer 23

oh okay i see where you got the numbers. So for the instantaneous rate of change for x=2 would it be 0 as well or 2?

Answer 24

@sithsandgiggles

Answer 25

Where is the problem?