Question

2. Using the description below, illustrate and label the process that is being completed with all the appropriate lab equipment.
a) A student diluted a copper (II) sulphate pentahydrate stock solution by placing a 1 mL of stock in 3 mL of dH2O.
b) The sample prepared in step a) was further diluted by placing 0.50 mL of the copper (II) sulphate pentahydrate into 4.5 mL of dH2O.
c) Lastly, 3 mL of the sample prepared in step b) was added to 12 mL dH2O.




















What is the total dilution factor?





If one was told that the stock solution

Answer 1

a) 1:4 or \(\dfrac{1}{4}\)
b) 1:10 or \(\dfrac{1}{10}\)
c) 1:4 or \(\dfrac{1}{4}\)

multiply them.

Answer 2

How did you get those?

Answer 3

for example: a) a 1 mL of stock in 3 mL of dH2O.

there are 4 mL in total, and your initial was 1 mL

so the ratio is \(\dfrac{1}{4}\)

if you had 3 mL of stock and added 7 mL of water then you'd have \(\dfrac{3}{10}\), makes sense?