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Find the coordinates of the two points on the curve where the line tangent to the curve is vertical. x^2 + 2x + y^4 + 4y = 5 and dy/dx = (-(x=1))/(2(y^3 +1)) Thanks!
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I just want a hint. Thanks.
What do you mean by (-(x=1))/(2(y^3 +1))
that's the slope of the tangent line
I mean the equal sign next to the x, is that supposed to be there?
oh sorry! i meant a plus sign there.
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Ok so the clue is in the question, if it is a tangent vertical line, what would it's gradient be? (If it was horizontal it would be 0)
zero? and when you refer to gradient, are you talking about the slope/derivative?
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