Solve for all x such that
(2x+1)^2 + 13(2x+1) +27 =0

Question

Solve for all x such that 
(2x+1)^2 + 13(2x+1) +27 =0

jdoe0001 · Answer

I'm thinking you may wan to use the quadratic formula

rizags · Answer

i have to use completing the square

jigglypuff314 · Answer

I don't think it is possible to find x by completing the square for this equation.
in any case, I was only able to factor it out to 4x^2+30x+41=0
and if you want an answer for x, I think it would come out to (1/4)((root(61))-15)
which approximates out to about -5.7026 and/or -1.7974
I hope this helps a little...

solomonzelman · Answer

(2x+1)^2 + 13(2x+1) +27 =0       factor out
4x^2+4x+1+26x+13+27=0         simplify
4x^2+30x+41=0                          you can start completing the square now
(2x+7.5)^2+41=0+56.25             see how I am doing this?

solomonzelman · Answer

now subtract 41 from each side
(2x+7.5)^2+41-41=56.25 -41
(2x+7.5)^2=15.25        square both sides
2x+7.5= √(15.25)        can you do it from there?

rizags · Answer

yes, thank you

solomonzelman · Answer

mention my name for help!

rizags · Answer

sure

solomonzelman · Answer

I mean in the future....
Glad I helped you!