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Chemistry 18 Online
OpenStudy (anonymous):

How many grams of NH3 are needed to provide the same number of molecules as in 0.95 grams of SF6? SF6 has 146.048 g/mol and I set up .95 g into (1 mol/146.048 g) and got .0065 moles. Now what do I do with the 1 mole = 6.022 × 1023 molecules into the .0065?

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