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Simplify the expression sin(x+pi)/cos(x-pi)
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Use these identities:\[\sin(a\pm b)=\sin a\cos b\pm \sin b\cos a\\ \cos(a\pm b)=\cos a\cos b\mp \sin a\sin b\]
Thank you, but I still don't get it. Could you show me what the first step would be?
\[\frac{\sin(x+\pi)}{\cos(x-\pi)}=\frac{\sin x\cos \pi+\sin \pi\cos x}{\cos x\cos \pi+\sin x\sin \pi}\] What are the values of \(\sin \pi\) and \(\cos \pi\)?
0 and -1, so would the answer be cotx?
Close, you have a sine in the numerator and cosine in the denominator.
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Oh woops, so tanx?
Yes
Thank you so much! (:
yw!
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