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Mathematics 13 Online
OpenStudy (anonymous):

Simplify the expression sin(x+pi)/cos(x-pi)

OpenStudy (anonymous):

Use these identities:\[\sin(a\pm b)=\sin a\cos b\pm \sin b\cos a\\ \cos(a\pm b)=\cos a\cos b\mp \sin a\sin b\]

OpenStudy (anonymous):

Thank you, but I still don't get it. Could you show me what the first step would be?

OpenStudy (anonymous):

\[\frac{\sin(x+\pi)}{\cos(x-\pi)}=\frac{\sin x\cos \pi+\sin \pi\cos x}{\cos x\cos \pi+\sin x\sin \pi}\] What are the values of \(\sin \pi\) and \(\cos \pi\)?

OpenStudy (anonymous):

0 and -1, so would the answer be cotx?

OpenStudy (anonymous):

Close, you have a sine in the numerator and cosine in the denominator.

OpenStudy (anonymous):

Oh woops, so tanx?

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

Thank you so much! (:

OpenStudy (anonymous):

yw!

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