Question

due in 8 min... Please help
Consider the curve x^{6} + 6 xy + y^{3} = 8
The equation of the tangent line to the curve at the point (1,1)
find m and b where y =mx +b

Answer 1

i got -15/6 for the m and 21/6 for the b but it says its wrong

Answer 2

I got y = -2/3x + 5/3. Is that the right answer?

Answer 3

\[ x^{6} + 6 xy + y^{3} = 8\]
\[6x^2+6(xy'+y)+3y^2y'=0\] put \(x=y=1\) and solve for \(y'\)

Answer 4

thanks