Question

Can you describe and fix what I did wrong here?
ax+b=0
ax=b
x= b/a

and the same thing goes for this one:
c= ax-bx
c= (a-b)x
c(a-b)=x

Answer 1

or better yet,
\[3x+2=0\]?

Answer 2

Thanks for helping but I'm still confused.

Answer 3

ok lets solve
\[3x+2=0\] step one: subtract \(2\) and get
\[3x=-2\] step 2) divide by 3 and get
\[x=-\frac{2}{3}\]

Answer 4

do the same thing here
\[ax+b=0\] step one: subtract \(b\) and get \[ax=-b\] (you missed the minus sign)
step 2) divide by \(a\) \[x=-\frac{b}{a}\]

Answer 5

clear or no? if not maybe i can explain more
if so we can go on to the next one, because you were close

Answer 6

Ohh thanks:) Could you help me with the second one? Oh and I woildn't have got that without you! Haha;) Thanks a lot.

Answer 7

ok your first two steps were good \[c= ax-bx \\
c= (a-b)x\]

Answer 8

but to get \(x\) by itself, you do not multiply by \(a-b\) but rather you need to DIVIDE by \(a-b\)

Answer 9

Okay.. Yay:)

Answer 10

Ohhhh

Answer 11

just like if you had
\[4=10x\] you would get \(\frac{4}{10}=x\)

Answer 12

Thanks a bunches!! Hey how old are you anyway? You're really smart!

Answer 13

when i say "divide" i don't really mean "do a division" but just write it
\[c=(a-b)x\\
\frac{c}{a-b}=x\]

Answer 14

Yep I got that thanks!

Answer 15

ok good
you familiar with black pepper?

Answer 16

Yes, why?

Answer 17

i am older than black pepper

Answer 18

BAHAHAH I THOUGHT YOU MEANT THE SALT AND PEPPER WAY!

Answer 19

lol