Mathematics
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OpenStudy (anonymous):
Integrate (2x-1)/(3)
I'm not so sure how to do this so any help would be appreciated. Thanks
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zepdrix (zepdrix):
\[\Large \int\limits \frac{2x-1}{3}dx\]So that's our integral? :)
OpenStudy (anonymous):
Yes
OpenStudy (anonymous):
I'm not so sure how to rearrange it into a simpler form for integrating
OpenStudy (anonymous):
Using the definition of the integral?
OpenStudy (anonymous):
Or using integral properties?
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OpenStudy (anonymous):
Well this is part of a question to find the area of a shaded segment
OpenStudy (anonymous):
Well do you know how to do this: \[
\int x \;dx
\]?
OpenStudy (anonymous):
= x^2/2
OpenStudy (anonymous):
Okay. Well \[
\int \frac{2x+1}{3}dx = \frac{1}{3}\left( \int2x\;dx+\int dx\right)
\]
OpenStudy (anonymous):
Does it equal to 1/3x^2
?
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OpenStudy (anonymous):
you're missing a term.
OpenStudy (anonymous):
Well what is \[\int\limits dx\]? I'm not so sure because we never learnt it...
OpenStudy (anonymous):
\[
\int dx=x+C
\]
OpenStudy (anonymous):
So the answer is
\[\frac{ 1 }{ 3 }x^{2}\]
?
OpenStudy (anonymous):
If \(f(x)dx= dx\) then what is \(f(x)\)?
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OpenStudy (anonymous):
1?
OpenStudy (anonymous):
Oops make that 1/3x^2 + x
OpenStudy (anonymous):
+C
OpenStudy (anonymous):
Ok thanks so much!