Question

Graph the line with slope -1/2 and y-intercept 2.

A. http://roads.advancedacademics.com/ContentServer/Content/RoadsSection/70755/image010.jpg

B. http://roads.advancedacademics.com/ContentServer/Content/RoadsSection/70755/image012.jpg

C. http://roads.advancedacademics.com/ContentServer/Content/RoadsSection/70755/image014.jpg

D. http://roads.advancedacademics.com/ContentServer/Content/RoadsSection/70755/image016.jpg

Answer 1

@nincompoop

Answer 2

hey :)

Answer 3

y = mx + b
your equation says
-1/2 slope and intercept is 2
so that's
y = -1/2x + 2

Answer 4

slope is rise over run correct?
that is change in y over change in x
for every 1 rise, you have 2 run

Answer 5

so is it C?

Answer 6

This can be solved by a process of elimination. We are given two key bits of information, namely that the slope is equal to -1/2 and that the y-int is 2.

The slope is negative, which means the graph of the line will descend as it moves left to right. Graph A ascends left to right, which means it has a positive slope which we don't want. Graph D neither ascends or descends, meaning it has a slope of 0, which we are not looking for.

A y-intercept is the point on the graph where the line crosses the y-axis. A y-int = 2 means the line crosses the y-axis at the number 2. Both graph B and C cross the y-axis at 2. This leaves us again relying on the slope.

A higher absolute value of your slope means it will have a steeper incline or decline (in our case, with a negative slope, decline). 1/2 has a less steep decline than a slope of 1 will have. One of your remaining graphs (B and C) has a slope of one, and the other has a slope of 1/2. The graph with a slope of 1/2 is less steep than the graph with a slope of 1, and is therefore your answer.

Answer 7

so its B! thanks nin! i love u!