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Approximate sin (12π)/13 by using a linear approximation with f (x) =sin x.
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Note that a = 3π/12 = π/4 is close to 3π/13, with h = π/4 - 3π/13 = π/52. Now, we compute c. f(x) = cos x, f '(x) = -sin x. Thus, cos (3π/13) ≈ cos(π/4) + (-sin(π/4)) · π/52 ≈ 0.664 (to three decimal places). (i.e., c ≈ 0.664.)
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