A water trough is 13 feet long, and its cross section is an equilateral triangle with sides 4 feet long. Water is pumped into the trough at a rate of 10 cubic feet per second. What is the height h of an equilateral triangle of side length s? How fast is the water level rising when the depth of the water is 1/2 foot?

Question

hitaro9 · Answer

I'm kinda lost as to what this problem is even supposed to look like.

zepdrix · Answer

|dw:1381216770055:dw|I think this might be the shape we're looking for.

zepdrix · Answer

They give us some information:
$\Large V'=10$, The rate at which water is coming in.

And they want us to find $\Large h'$, the rate at which the water is rising, when $\Large h=\dfrac{1}{2}$.

zepdrix · Answer

|dw:1381217155704:dw|Hmm...

wolf1728 · Answer

Height of the trough² is 4² - 2² = 12
trough height = sqrt(12) = 2*sqrt(3) = 3.464