8. What volume of oxygen is required for the complete combustion of a mixture of 5 cm3 of CH4 and 5 cm3 of C2H4 ? I just want help . not the ANSWER please .thank you :)
@JMark @atlas @madrockz @thomaster
Start with the reaction equation
reaction of methane with oxygen @thomaster
after complete combustion everything becomes Co2 and water
d = m/V ???
what's that?
density = mass / volume . Is i have to put this ??
now why would you need density?
um...to find volume of oxygen I think so ...
PV = nRT is valid for all gases at standard conditions So if Pressure and Temperature are constant equal volume will contain equal moles SOlve the question using moles and replace them with volume afterwards
You need to convert cm3 to moles. In this case that's easy since 1 mol gas = 22.4 liter. 1 liter = 1000 cubic centimeters
@thomaster i don't think that is necessary
um ..getting confused :/
Since moles and volume are equivalent here........................solving the question in volume is sufficient
Yea just start with writing the chemical equation \(\Large CH_4+O_2\to?\)
ok ..:)
CH4 + 2O2 ---> CO2 + 2H2O ..
That's correct :)
so the next step please :) ??
Now the mol ratio is: 1 mol CH4 reacts with 2 mol O2 to produce 1 mol CO2 and 2 mol H2O we only need the first part: 1 mol CH4 reacts with 2 mol O2, so CH4:O2 = 1:2 We have 5cm3 CH4, how many cm3 O2 would we need?
10cm3 ...
exactly :D Now can you do the same for the second one? C2H4?
C2H4 + 3O2 --> 2CO2 + 2H2O so C2H4 : O2 = 1 : 3 for 5cm3 of C2H4 we need 15 cm 3 O2
@thomaster
correct \(\LARGE\ddot\smile\)
so our answer is 25 cm 3 O2 ...:D
no 5 * 3 = 15 O2
@thomaster : she was saying the overall answer
@sarah786 : you are right
oh that way, in that case 10+15 = 25 yea
yeah overall answer :)
Thanks you so much guys :)...But this is the only one .I need your help for more problems too ..so I'll tag you when I need ur help ..ok :) ??
sure :)
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