2x-1y=8 1x+2y=9
substition or elimination
well what does x equal
you can use any method other than matrices
ok which one do you prefer for this problem :)
elimination if thats ok
sure try to make either x, or y the same coefficient in both equations the sign does not matter, just the value
okay hold just asec
you can multiply an equation by some number: multiply every term with this number left and right to keep what equation states the same.
im a little confused right now
no problem if you have some equation, example: 2x+1 = y then you can multiply everything by 3 left and right, and get example: 6x+3 = 3y the "balance" of the equation is still the same, just the values are all bigger.
if this is clear, you know that you can multiply every term by some number whenever it makes sense to you. it's a valid operation
so to get -1y to match 2y we would multiply it by -2?
YES EXACTLY
alright so we would get 2x+2y=-16?
2x was not changed: every term must be multiplied, every single one if they're with a + between them, they count as seperate terms then they both need separate, treatment
8 was treated (correct) -1y was treated (correct) 2x was LEFT OUT !!ERROR!!
so 4x+2x+-16
uh uh uh, 2x times -2 changes the sign of x :)
oops yea so -4x+2y+-16 :(
very good
ok so what is the next step?
now, we can subtract one from the other to ELIMINATE Y
1x +2y = 9 -( -4x +2y = -16 ) -------------------
2x-1y=8....Eq:1 1x+2y=9....Eq:2 by substitution method taking Eq:1 and separate x 2x=8-y x=8-y\2.....Eq(3) now put Eq:3 in Eq:2 8-y\2+2y=9 by the L.C.M \[\frac{ 8-y+4y }{ 2 }=9\] 8-3y=18 -3y=18-8 -3y=10 y=-10\3 now put the value of y in Eq 3 \[\frac{ 24-10 }{ 3 }\2\] 14\6 7\3 x = 7\3 ,, y =-10\3
so the subtraction just turns around the sign of every term: then we can add: 1x +2y = 9 +4x -2y = +16 -------------
it turns out that adding the -1 is the same as subtracting it 9 minus 4 = 5 9 plus -4 = ....5. that's why the method above works (subtracting by adding sign changed)
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