Question

Given the system of constraints, name all vertices of the feasible region. Then find the maximum value of the given objective function.
x>0
y>0
y<1/3x+3
5>y+x
Objective Function: C = 6x – 4y

Answer 1

x>0, y>0 tell us that only points in the first quadrant are part of the solution

do you agree?

Answer 2

I have no idea what I'm doing here...I don't just want the answers I would like an explanation so I can do it in the future

Answer 3

@mathessentials

Answer 4

yep, I'm giving all explanations there are :)

do you know what quadrants are? and, am I doing it right?

Answer 5

yes I know what quadrants are...

Answer 6

yeah sure ok then we can talk about them :),

so if x>0, y>0 only the following space remains:

Answer 7

ok I got that because x is greater than 0 and same with y

Answer 8

exactly, so these two constraints simply tell us the 1st quadrant remains

Answer 9

these are left:
y<1/3x+3
5>y+x

Answer 10

they pose further restrictions on the solution area, the feasible area

Answer 11

ok

Answer 12

they are inequality lines and we should also draw them