Help 5 questions
@nincompoop
I could easily answer but I wouldn't know how to show my work xD wolframalpha.com
I gave you a website to use~
@zepdrix @Nurali @e.mccormick @agent0smith @amistre64 @nubeer @hba
LxairaS.... I GAVE you a website that will give you the answer along with the step by step solution
i couldnt find the correct answer
for which question?
nvm ill get help from @Nurali
for #5: type in "factor 4x^2+5x-6" and it'll give you the direct answer...
@e.mccormick can you help?
Well, did you try factoring it?
i think for 1 its 0 or a
\(4x^2+5x-6 \) starts with a 4. The factors of 4 are 4 and 1 or 2 and 2. None of the answers starts with a 2, so you can skip looking at those.
ohh okay 5 is b? i wa stalking about 1 lol
It has a negative because the -6 at the end. The middle is +5, so the + part must be larger than the negative. There is also a formula for finding these but I don't remember it off the top of my head. However, with just those three pieces of information, I was able to find the factors.
Ah, 1. Hehe. you were talking about 5 with the other guy. As for the first two, they are both discriminant problems. Did you use that part of the quadratic to find it?
let me see if i can figure them out lol ill tell you when im done k :)
\(b^2-4ac\) is all you need. From \(ax^2+bx+c\) form.
1 is a 0 right ?
@e.mccormick
No.
how?
is it 32 right?
i subtraced the 16s when i was supposed to add
@e.mccormick i think 2 is either b or c
\(4^2-4(2)(-2) = 16+16=23\) so yah.
oops typoed there. 32.
is 2 c 2 irrational solutions?
\(4^2-4(2)(4) = 16-32 = -16\) Now, the \(\sqrt{-16}\) is that irrational, or is there another word for it?
since -16 is not a perfect square?
@e.mccormick ?
Goes back to number systems. Look for \(\sqrt{-1}\) http://www.mathnstuff.com/math/spoken/here/2class/0/c0pg00.htm
so its complex?
Yah, whn a root is negative it is going to make what is called a pair of complex conjugates. Because of the \(\pm\) nature of roots they always come in pairs.
okay for 3 my answer is c for 4 my answer is d for 5 my answer is b am i correct?
5 is b. I have not done the others yet. Let me look....
k
3 yah.
If I give e.mccormick a medal for showing work, will you give me one for answering the questions, lxairaS?
4, yah d.
yes give one to @e.mccormick
@e.mccormick is 3 c @whalexnuker give a medal to @e.mccormick
If there is ever a question of me vs someone else getting a medal, don't bother giving me one. I do not care about medals.
ohh k is 3 c?
Yes. That is what my 3 yah meant.
Thanks @e.mccormick :)
and @whalexnuker tahnks for the help :)
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