Question

9. A gaseous organic compound, X, was burnt in an excess of oxygen. A 0.112 dm sample of X, measured at s.t.p., produced 0.88 g of carbon dioxide.
How many carbon atoms are there in one molecule of X?

Answer 1

@thomaster

Answer 2

@JFraser @Luigi0210 @Nurali

Answer 3

its .0112 dm 3

Answer 4

please delete all name.

Answer 5

why ? I just tag them so they can help me ..Not the Answer ..

Answer 6

if you know how many grams of \(CO_2\) are produced, then you know how many moles of \(CO_2\) are produced.

if you know how many moles of \(CO_2\) are produced, then you know how many molecules of \(CO_2\) are produced.

if you know how many molecules of \(CO_2\) are produced, each molecule of \(CO_2\) must contain ONE atom of C.

Find the proper ratios

Answer 7

First, you need to determine how many moles of the gaseous compound you began with. Since you are at STP, you know that 1 mole of any gas at STP occupies a volume of 22.4 dm^3. So,

0.112 dm^3 / 22.4 dm^3/mol = 5.00X10^-3 moles of gas X

Now, from the mass of CO2 formed, you can calculate the moles of CO2 (and thus the moles of C in the compound:

0.88 g CO2 / 44.0 g/mol = 0.02 moles CO2 = 0.02 moles C

Dividing moles of C by the moles of the original compound will give you the number of carbon atoms per molecule:

0.02 / 0.005 = 4.

So, the compound contains 4 carbon atoms per molecule.

Answer 8

I need help .not the whole question solved by you ..you could help me by telling me step by step procedure @Nurali

Answer 9

Thank you so much @Nurali and @JFraser

Answer 10

Anytime.