Question

After 54 min, 20.0% of a compound has decomposed. What is the half-life of this reaction assuming first-order kinetics?

Answer 1

use this formula: \(\huge A_t=A_0*e^{(\frac{-0.693t}{t_{1/2}})}\)


t is time, \(t_{1/2}\) is the half life
A_t is amount after t time has elapsed
\(A_0\) is the initial amount

Answer 2

Can you continue to help me