Question

What is the equation of the line that passes through (–2, 3) and is parallel to 2x + 3y = 6?

A. Y = 2x+6
B. Y = -2/3x + 5/3
C. Y = 2x + 3
D. Y = 2/3x + 5/3

Answer 1

Put the equation in slope intercept form.

Answer 2

Y=mx+b?

Answer 3

Yup

Answer 4

y=2x+3 i think?

Answer 5

Not exactly

Answer 6

Im on a timed test can I get the answer please? Im about to fail if I dont get this

Answer 7

Okay, so we have this:
\[\large 2x+3y=6\]
And we need to get it to look like this:
\[\Large y=mx+b\]
So we need to get y by itself.
We subtract 2x from both sides:
\[\large 2x-2x+3y=6-2x\]
Simpliffy and we get this:
\[\large 3y=6-2x\]
Now we just divide everything by 3, and we end up with:
\[\large y=2-\frac{2}{3}x\]
Or in slope intercept form:
\[\large y=-\frac{2}{3}x+2\]

Answer 8

make sense?