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related rates:) An inverted cone with height 10 cm and radius 2 cm is partially filled with liquid which is oozing out through the sides at a rate proportional to the area of the cone in contact with the liquid. (The area of a cone is pi(r)(l) where r is the radius and l is the slant height of the cone) Liquid is also being poured in to the top of the cone at a rate of 1 cm^3/min. At what rate must liquid be poured into the top of the cone to keep the liquid at a constant depth of 4 cm?
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@hartnn
|dw:1381274824776:dw|
\[A_{cone} = \pi r l\]\[V_{cone}=\frac{ 1 }{ 3 }\pi r^2 h\]
|dw:1381275156973:dw|
|dw:1381275261630:dw|
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