A 12.82 g sample of a compound contains 4.09 g potassium (K), 3.71 g chlorine (Cl), and oxygen (O). Calculate the empirical formula.
convert all the masses to moles, divide them all by the species with least moles. Normalize the moles into integers.
So would I go 12.8*1/4.09 to find K?
you have to convert the masses to moles first
\(n=\dfrac{4.09 g}{Molar\;mass\;of\;K}\)
So K is 39/1 mol so 4.09/39?
yes, do that for Cl and for O, as well.
.10487179 K, .10465444 Cl, 0.2 O So I would divide them all by Cl right and then round up to the nearest integer?
so K = 1, O =I got .5 and I have no idea how to get Cl
so K=1, then Cl=1, and O=2 \(KClO_2\)
Hmm I think I messed up somewhere...
That KClO2 formula is wrong...I don't think I used the 12.8 correctly
so your masses were K 4.09 g Cl 3.71 g O = 12.82 g- (4.09 g + 3.71 g)
what did you get for moles?
I got the 0.2
0.2 for moles of oxygen?
Yeah, is that where I messed up?
what mass did you use?
7.8/15.999 = .4875. Is this the actual answer for moles?
i don't think there are 7.8 grams of oxygen
Oops forgot to subtract it from 12.82, so 5.2/15.999= .325
now divide
.10465444/.325 = .322
no divide everything by the lowest number
.10465444 is the lowest number
you didn't divide by the lowest number here: .10465444/.325 = .322
Ok I'm lost again
okay, lets step back. what are your mole values?
.10465444 for Cl, .10487179 for K, and .325 for O
okay, now divide everything by the lowest number
.10465444/.10487179 = .99 = 1, and .1046544/.325 = .322
Now what?
Tokyo down can you hel. Me
In chem it is posted there
you're still doing this wrong: ".1046544/.325 = .322" i asked you to divide by the smallest number, as in: .325/.1046544
ok so 3.10545831 .1046/.1068 = 1.00207
so your final formula is \(KClO_3\)
Join our real-time social learning platform and learn together with your friends!