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how do i prove d/dx cos(x^2)=-2sin(x^2) is true/false?
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Ahhhh headache
take the derivative using the chain rule and see that you get something different
the derivative of \(x^2\) is \(2x\) so the correct answer is \[-2x\sin(x^2)\]
but im confused as hot to start the chain rule...
how*
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the derivative of \(\cos(x)\) is \(-\sin(x)\) by the chain rule the derivative of \(\cos(f(x))\) is \(-\sin(f(x))\times f'(x)\)
so you get -sin(x^2) x 2x and we get -2xsin(x^2)?
thank you!!
yes yw
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