Explain the shape...
@abb0t can you help me understand why this is wrong?
It has 3 on the equitorial and 2 on the axial...
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Is that the geometry?
It looks like this. I think your drawing is right.
Hm, it should be that then. I don't know why it's wrong. Unless I am seeing it wrong.
Let me take a few for shots from diff. angles.
Compare the geometry PCl\(_5\). If they are the same, it should be trigonal bipyramidal. If not, then the geometry is different.
My book says PCl5 is trig. bi pryd
Anything higher would be octahedral geometry and that isn't right for a species with 3 atoms attached at equitorial position.
I agree. But take a look at this other problem the homework gave...I thought it was stupid as well. Maybe it will help on this one?
I wonder if the three atoms that are highlighted in the equitorial position have anything to do with the answer. Did you try trigonal planar?
What is wrong with the other one?
Why is the one a tetrahedral?
...And trigional planar did not work....
Because PCl\(_3\) has a lone pair electron on the "y-axis"
Remember that lone-pairs basically create a dipole-moment for the atoms, pushing them down slightly. And since the atoms are pushed downward slightly, this creates a tetrahedral geometry. Doest that make sense?
I wish you could see the pic of it my book gives, it is so confusing.
And the trigional planar did not work.\
@abb0t
why are the equatorial ligands lit up in blue? does that signify that their electron pairs?
Actually the homework wanted me to do that for part A.
@aaronq
I have tried trig. pyramidal and tetrahedral to no avail.
if the blue atoms are electron pairs, the molecule is linear
It says that they are equatorial atoms.@aaronq
if they're actual atoms then it's definitely trigonal bipyramidal.
i noticed you spelled it wrong in the picture you posted, do you think that could be the problem?
Wow. That was it.
All this over spelling. :(
Thank YOU!
lol darn computers! no problem dude
By the way, that little oval shape circle thing that is shown in your book is actually representative of an electron cloud. Meaning, there is an electron lone pair there. Just so you know.
Sorry for the late response, I went to bed early. But I was certain someone would come and help soon.
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