A roadside vegetable stand sells pumpkins for $5 each and squashes for $3 each. One day they sold 6 more squash than pumpkins, and their sales totaled $98. Write and solve a system of equations to find how many pumpkins and squash they sold?
How do I do this?

Question

A roadside vegetable stand sells pumpkins for $5 each and squashes for $3 each. One day they sold 6 more squash than pumpkins, and their sales totaled $98. Write and solve a system of equations to find how many pumpkins and squash they sold? 
 How do I do this?

anonymous · Answer

p = s - 6 
5p + 3s = 98

now sub s - 6 in for p in the other equation and solve for s. Once s is found, sub that value back into either of the original equations and find x

anonymous · Answer

or you could use this as the first equation...s = p + 6.
either one will work

anonymous · Answer

I'm confused.

anonymous · Answer

6 squashes cost $18  
98-18=$80
80/(5+3)=10 pumpkins

anonymous · Answer

p = s - 6
now lets sub s - 6 in for p in the other equation
5p + 3s = 98
5(s - 6) + 3s = 98
5s - 30 + 3s = 98
8s - 30 = 98
8s = 98 + 30
8s = 128
s = 128/8
s = 16

now sub 16 in for s in either of the original equations
p = s - 6
p = 16 - 6
p = 10

10 pumpkins and 16 squash

Was that what you were having trouble with or was it just setting up the equations ?

goformit100 · Answer

"Welcome to OpenStudy. I can guide regarding this useful site; ask your doubts from me, for it you can message me. Please use the chat for off topic questions. And remember to give the helper a medal, by clicking on "Best Answer". We follow a code of conduct, ( http://openstudy.com/code-of-conduct ). Please take a moment to read it."